integral tentu
2 mendekati -1 (x^3+3x^2+4x+5) dx
2 mendekati -1 (x^3+3x^2+4x+5) dx
Jawab:
integral tentu
₋₁²∫ x³ + 3x² + 4x + 5 ) dx
= ¹/₄ x⁴ + x³ + 2x² + 5x]²₋₁
= ¹/₄ (16- 1) + (8+ 1) + 2(4 -1) + 5(2 +1)
= ¹⁵/₄ + 9 + 6+ 15
= 33 ³/₄